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18-19年期中考试试卷

浙江大学2018-19秋冬《数据结构基础》期中模拟练习

浙江大学2018-19秋冬《数据结构基础》期中模拟练习
开始时间01/01/2016 8:00:00 AM
结束时间01/18/2038 8:00:00 AM
答题时长90分钟
考生
得分19
总分100

判断题得分:12总分:15
R1-1

2N2^N and NNN^N have the same speed of growth.

(3分)
评测结果答案错误(0 分)
R1-2

If keys are pushed onto a stack in the order {1, 2, 3, 4, 5}, then it is impossible to obtain the output sequence {3, 4, 1, 2, 5}.

(3分)
评测结果答案正确(3 分)
R1-3

If there are less than 20 inversions in an integer array, then Insertion Sort will be the best method among Quick Sort, Heap Sort and Insertion Sort.

(3分)
评测结果答案正确(3 分)
R1-4

For a sequentially stored linear list of length NN, the time complexities for query and insertion are O(1)O(1) and O(N)O(N), respectively.

(3分)
评测结果答案正确(3 分)
R1-5

In a binary search tree, the keys on the same level from left to right must be in sorted (non-decreasing) order.

(3分)
评测结果答案正确(3 分)
单选题得分:5总分:64
R2-1

The recurrent equations for the time complexities of programs P1 and P2 are:

  • P1: T(1)=1T(1)=1, T(N)=T(N/2)+1T(N)=T(N/2)+1;
  • P2: T(1)=1T(1)=1, T(N)=2T(N/2)+1T(N)=2T(N/2)+1;

Then the best conclusion about their time complexities is:

(5分)
评测结果答案错误(0 分)
R2-2

To delete p from a doubly linked list, we must do:

(5分)
评测结果答案错误(0 分)
R2-3

Given input {15, 9, 7, 8, 20, -1, 4}. If the result of the 1st run of Shell sort is {15, -1, 4, 8, 20, 9, 7}, then the initial increment must be:

(5分)
评测结果答案错误(0 分)
R2-4

In-order traversal of a binary tree can be done iteratively. Given the stack operation sequence as the following:

push(1), push(2), push(3), pop(), push(4), pop(), pop(), push(5), pop(), pop(), push(6), pop()

Which one of the following statements is TRUE?

(5分)
评测结果答案错误(0 分)
R2-5

How many leaf node does a complete binary tree with 2435 nodes have?

(5分)
评测结果答案错误(0 分)
R2-6

Suppose that an array of size m is used to store a circular queue. If the head pointer front and the current size variable size are used to represent the range of the queue instead of front and rear, then the maximum capacity of this queue can be:

(5分)
评测结果答案错误(0 分)
R2-7

Given input { 4321, 56, 57, 46, 28, 7, 331, 33, 234, 63 }. Which one of the following is the result after the 1st run of the Least Signification Digit (LSD) radix sort?

(5分)
评测结果答案正确(5 分)
R2-8

Given a quadtree(四叉树) with 4 nodes of degree 2, 4 nodes of degree 3, 3 nodes of degree 4. The number of leaf nodes in this tree is __.

(5分)
评测结果答案错误(0 分)
R2-9

For an in-order threaded binary tree, if the pre-order and in-order traversal sequences are B E A C F D and A E C B D F respectively, which pair of nodes' left links are both threads?

(4分)
评测结果答案错误(0 分)
R2-10

The result of performing three DeleteMin operations in the min-heap {1,3,2,12,6,4,8,15,14,9,7,5,11,13,10} is:

(5分)
评测结果答案错误(0 分)
R2-11

For the quicksort implementation with the left pointer stops at an element with the same key as the pivot during the partitioning, but the right pointer does not stop in a similar case, what is the running time when all keys are equal?

(5分)
评测结果答案错误(0 分)
R2-12

Among the following sorting methods, which ones will be slowed down if we store the elements in a linked structure instead of a sequential structure?

  1. Insertion sort; 2. Selection Sort; 3. Bubble sort; 4. Shell sort; 5. Heap sort
(5分)
评测结果答案错误(0 分)
R2-13

Insert { 3, 8, 9, 1, 2, 6 } one by one into an initially empty binary search tree. The post-order traversal sequence of the resulting tree is:

(5分)
评测结果答案错误(0 分)
程序填空题得分:0总分:15
R5-1

The function is to find the K-th smallest element in a list A of N elements. The function BuildMaxHeap(H, K) is to arrange elements H[1] ... H[K] into a max-heap. Please complete the following program.

ElementType FindKthSmallest ( int A[], int N, int K )
{   /* it is assumed that K<=N */
    ElementType *H;
    int i, next, child;

    H = (ElementType *)malloc((K+1)*sizeof(ElementType));
    for ( i=1; i<=K; i++ ) H[i] = A[i-1];
    BuildMaxHeap(H, K);

    for ( next=K; next<N; next++ ) {
        H[0] = A[next];
        if ( H[0] < H[1] ) {
            for ( i=1; i*2<=K; i=child ) {
                child = i*2;
                if ( child!=K && (3分) ) child++;
                if ( (3分) )
                    H[i] = H[child];
                else break;
            }
            H[i] = H[0];
        }
    }
    return H[1];
}

序号结果测试点得分
0编译错误0
1未作答0
评测结果多种错误(0 分)
R5-2

The function is to sort the list { r[1] … r[n] } in non-decreasing order. Unlike selection sort which places only the minimum unsorted element in its correct position, this algorithm finds both the minimum and the maximum unsorted elements and places them into their final positions.

void  sort( list r[], int n )  
{
   int i, j, mini, maxi;

   for (i=1; i<n-i+1; i++) {
      mini = maxi = i;
      for( j=i+1; (3分); ++j ){
         if( (3分) ) mini = j; 
         else if(r[j]->key > r[maxi]->key) maxi = j;
      }
      if( mini != i ) swap(&r[mini], &r[i]);
      if( maxi != n-i+1 ){
         if( (3分) ) swap(&r[mini], &r[n-i+1]);
         else swap(&r[maxi], &r[n-i+1]);
      }
   }
} 
评测结果未作答(0 分)
函数题得分:2总分:6
R6-1
No Less Than X in BST
(6分)

You are supposed to output, in decreasing order, all the elements no less than X in a binary search tree T.

Format of function:

void Print_NLT( Tree T,  int X );

where Tree is defined as the following:

typedef struct TreeNode *Tree;
struct TreeNode {
    int Element;
    Tree  Left;
    Tree  Right;
};

The function is supposed to use Output(X) to print X.

Sample program of judge:

#include <stdio.h>
#include <stdlib.h>

typedef struct TreeNode *Tree;
struct TreeNode {
    int Element;
    Tree  Left;
    Tree  Right;
};

Tree BuildTree(); /* details omitted */
void Output( int X ); /* details omitted */

void Print_NLT( Tree T,  int X );

int main()
{
    Tree T;
    int X;

    T = BuildTree();
    scanf("%d", &X);
    Print_NLT( T, X );
    printf("End\n");

    return 0;
}

/* Your function will be put here */

Sample Output 1 (for the tree shown in Figure 1):

92 91 90 85 81 80 End

Figure 1

Sample Output 2 (for the tree shown in Figure 2):

End

Figure 2
编译器
GCC
代码
void Print_NLT( Tree T,  int X ) {
    return;
}
编译器输出
a.c: In function ‘BuildTree’:
a.c:33:6: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
      scanf("%d", &n);
      ^~~~~~~~~~~~~~~
a.c:35:10: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
          scanf("%d", &x);
          ^~~~~~~~~~~~~~~
a.c: In function ‘main’:
a.c:52:5: warning: ignoring return value of ‘scanf’, declared with attribute warn_unused_result [-Wunused-result]
     scanf("%d", &X);
     ^~~~~~~~~~~~~~~
测试点结果测试点得分耗时内存
0答案错误05.00 ms316 KB
1答案正确14.00 ms384 KB
2答案错误05.00 ms356 KB
3答案正确14.00 ms324 KB
4答案错误05.00 ms400 KB
评测结果部分正确(2 分)